tentukan nilai x [1/12]^x-1 = [1/32]^x-1
Penjelasan dengan langkah-langkah:
[tex] {( \frac{1}{12} )}^{x - 1} = {( \frac{1}{32} )}^{x - 1} [/tex]
[tex] {( \frac{ \frac{1}{12} }{ \frac{1}{32} } )}^{x - 1} = 1[/tex]
[tex] {( \frac{32}{12} )}^{x - 1} = {( \frac{32}{12} )}^{0} [/tex]
[tex]x - 1 = 0[/tex]
[tex]x = 1[/tex]
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